If you are planning to fold them from sheet metal, why not use a different design and orient the material to provide better stiffness rather than use a thicker gauge?
If you cut and folded something like this, you could design strength at the parts which need to resist the most load.
Could drill each side and bolt together at midspan with a spacer for extra rigidity.
nice sketches brother, and I like where you’re going with this!!
Hmmmmmmmmmmmm
seems like all the sheer force would develop right at the end of the horizontal bend line at the board end… relatively easy to fixerate with a good sheet-metal design and a tig welder…
Cheers Kook.
Thought about a bunch of diy options for these a while ago.
I bought G Bombs instead. Haha. Lazy.
Probably could’ve had my mate who has a water jet to cut and fold something like this for me, now I think about it
If he just wants to cut and fold, he could try this in steel and bolt each side together and it’d be pretty strong.
I think it’s the board side connection where the weakness is. Lengthening that would help dissipate stress into the deck.
Assuming it’s 5052 like @MysticalDork said, the Yield strength is 193MPa (don’t aim at ultimate)
With your 70kg, you’re getting over it at 223MPa with a single 4mm sheet.
There are two problems with what you’re trying to do:
If you stack these two they won’t behave like 8mm, but rather like two springs in parallel. I might simulate this in FEM later just for fun.
When you bend (anything really) you’ve already exceeded the yield stress at the bend, so the behavior is more complicated (need to be accounted for)
Assuming you have a single 6mm sheet, the stresses go down to ~100MPa, for 8mm to ~60MPa
These numbers seem to compare better with what 5052 can do, then again I have no idea what happens at the bend.
I have to ask why? I mean drop through is good when you’re trying to lower your board, but you manufacture those, so just make a bigger vertical offset…
For quick and dirty bending stress estimates, use the following:
S=6M/(b*c^2)
S-stress
M-the bending moment
c-plate thickness
b-the width of the plate
I estimated the loads long time ago for a different purpose, but it still holds:
In your case it’s 70/2kg*(45+40mm)=~3kg.m (assuming the load from the truck acts at the middle of 90mm and the max stress is at the bend (sorry, I didn’t use cosine for the 40mm)…
So, notice what happens when we load the two stacked plates, notice the separation between the two, and bigger displacement (the scale is exaggerated for clarity):
Because I’m fixing the bolts on the right side there’s no additional need to “weld” there.
The weld in this analysis are only on the cantilevered part, like in the picture: