I also would have guessed less. Like I said, even at 0.1 C, it takes 10s of seconds or maybe a single minute to go from around 2.0 V to 2.5 V in my experience. One minute at 0.1 C would be 0.17% of the capacity. Maybe reverse sag tricked me, or it took way longer than I thought, but it seemed near instant to me.
I’m going off my memory of some testing last year but perhaps I’m in error. I’ll test it later today or tomorrow.
I’ve done work with AI/machine learning for a long time. I just don’t think LLMs are worth a shit. Garbage in, garbage out is the first thing anyone doing data science should learn, but for whatever reason, the current LLM hype seems to think that if you pour a mount of garbage in, you’ll somehow get a genius out.
All I see is a fancy autocomplete that acts like a confidently incorrect random person on the internet a lot. Also, I work in physics, and while I haven’t messed with the newest models, when the recent hype started, talking to AI about physics always ended up in effectively technobable that was about the quality of talking to a random conspiracy theory crackpot at a bar. If I’m going to talk to something like that, I at least need it to be in a bar so I have the necessary amount of alcohol to tolerate it.
Okay, no more multi-tasking for me…with a clearer mind now I am definitely wrong and I apologize for the confusion. Yes, you two are right, the capacity gain will be tiny. I have edited my post.
I’ll continue to do the test anyway…my penance I guess.
Okay, penance done…
Reliance RS40 drained from 2.498V to 1.000V at 100mA delivered 20mAh. Umm…yea…I was verrrrrry wrong.
Now to bring the cell to zero volts a couple of times, short it for a couple of hours, and then tear it apart. ![]()
reviving from 1v is described in the section related self-discharge with this data sheet but with other data sheets it’s written elsewhere.
In those other datasheets, is the spec for end-of-discharge and/or BMS shutoff above 1V? If so then the discharge must stop there and the only way 1V can be reached is via self-discharge or quiescent current draw from the BMS.
So I’m confused regarding your statement.