Need some input to finish up

that’s to win a race. I’ll show you what you’ll get at 50kmh with your current setup in a sec and with ideal ratio.

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@Flasher with 7.81 battery current limit per motor and 3.73:1 you can still reach 50kmh/31mph.

that’s about:
50kmh/0.65604kWh = 76.2km/kWh <----

or

31.07mph/0.65604kWh = 47.35mi/kWh <----

And if I keep it with my 15t/44t setup @ 50km/h? How many amps per motor and how much range would that give me? Btw I’m more close to 115lbs and my board will weigh close to 30

@Flasher I’ll calculate this next. Weight isn’t a factor on flat ground (at constant velocity) if you’re only factoring wind drag and slope forces.

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about 8.5a battery limit per motor:


with your current setup:

50kmh/~0.72kWh = 69.44km/kWh <----

or

31.07mph/~0.72kWh = 43.15mi/kWh <----

^so by not using the ideal ratio for 50km/h on flat ground you will be losing about 6.8 kilometers / 4.2 miles range per kWh. the wasted energy shows up as extra heat in your motor windings. note: these calculations are based on BLDC mode not FOC. (&i haven’t got the slightest clue how to calculate it for FOC, though I have calculated one particular situation where FOC mode was using ~8% less electrical watts for the same torque at the same rpm – this is explained by FOC using more of the copper mass in your motor on average at any given time – BLDC only uses 2/3 of the copper)

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Wow… You are impressive